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9. Answer: Option 'C' Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-" A number means = 100 % That same number increased by 20 % = 120 % 120 % -------> 480 (120 × 4 = 480) 100 % -------> 400 (100 × 4 = 400)
10. Answer: Option 'A' Let the marks secured by them be x and (x + 9) Then sum of their marks = x + (x + 9) = 2x + 9 Given that (x + 9) was 56% of the sum of their marks =>(x+9) = 56/100(2x+9) =>(x+9) = 14/25(2x+9) => 25x + 225 = 28x + 126 => 3x = 99 => x = 33 Then (x + 9) = 33 + 9 = 42 Hence their marks are 33 and 42
11. Answer: Option 'C' 20% of a = b => b = 20/100a b% of 20 = (b/100)20 = [(20/100a)/100]20 = (20 × 20 × a)/(100 × 100) = 4a/100 = 4% of a
12. Answer: Option 'C' Let the amount paid to X per week = x and the amount paid to Y per week = y Then x + y = 550 But x = 120% of y = 120y/100 = 12y/10 ∴12y/10 + y = 550 ⇒ y[12/10 + 1] = 550 ⇒ 22y/10 = 550 ⇒ 22y = 5500 ⇒ y = 5500/22 = 500/2 = Rs.250
13. Answer: Option 'A' Total cost of the items he purchased = Rs.25 Given that out of this Rs.25, 30 Paise is given as tax => Total tax incurred = 30 Paise = Rs.30/100 Let the cost of the tax free items = x Given that tax rate = 6% ∴ (25−30/100−x)6/100 = 30/100 ⇒ 6(25 −0.3 −x) = 30 ⇒ (25 − 0.3 − x) = 5 ⇒ x = 25 − 0.3 − 5 = 19.7
14. Answer: Option 'C' Quantity X Rate = Price 1 x 1 = 1 0.7 x 1.25 = 0.875 Decrease in price = (0.125/1) × 100 = 12.5%
15. Answer: Option 'A' State A and State B had an equal number of candidates appeared. In state A, 6% candidates got selected from the total appeared candidates In state B, 7% candidates got selected from the total appeared candidates But in State B, 80 more candidates got selected than State A From these, it is clear that 1% of the total appeared candidates in State B = 80 => total appeared candidates in State B = 80 x 100 = 8000 => total appeared candidates in State A = total appeared candidates in State B = 8000
16. Answer: Option 'B' Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-" A number means = 100 % That same number Decreased by 20 % = 80 % 80 % ------> 480 (80 × 6 = 480) 100 % ------> 600 (100 × 6 = 600)
21. Answer: Option 'A' A = 125 B = 100 A-B/A × 100 = 25/125 × 100 = 20 % smaller smaller than A
22. Answer: Option 'C' X = 120% Y = 125% Z = 100% X-Y/Y × 100 = 5/125 × 100 = 4 % smaller than Y
23. Answer: Option 'C' X = 80 % Y = 70 % Z = 100 % X-Y/X × 100 = 10/80 × 100 = 12 1/2 % greater than X
24. Answer: Option 'B' X = 120 Y = 100 Z = 80 X-Z/Z × 100 = 40/80 × 100 = 50 % greater than Z
25. Answer: Option 'A' Total = 100 %, First person got 60% second person got remaining 40 % of votes. than 40 % = 280 40% = 40×7 = 280 100% =100×7 =700votes
35. Answer: Option 'A' passed in Telugu = 60 % passed in English = 50 % only passed in telugu = 50% only passed in english = 40% the percentage of studebts passed in both the subjects = 10 %
36. Answer: Option 'B' only telugu passed = 50 % only english passed = 40 % both subjects passed student are 10 %, Then, 10 % ------> 120 100 % ------> 1200students
37. Answer: Option 'B' only t = 40,only e = 30 and both subjects passed 20% 10% failed in both subjects
38. Answer: Option 'C' (20 li = 4 li water 16 li milk -------- 5 li water Total = 9 li water 16 li milk (new) 16/25×100=64%
39. Answer: Option 'D' (30 li = 9 li water 21 li milk ------= 10 li water Total = 19li water 21 li milk (new) 19/40 × 100 = 47 1/2%
41. Answer: Option 'B' FORMULA: First value = last value×100/100-p1×100/100-p2×---------------- (p=percentage) First value = 5760×100/100 - 20×100/100 - 10×100/100 - 20 = 5760 × 100/80× 100/90× 100/80 = 10000/-
42. Answer: Option 'C' Let a family's monthly consumption of daal be x kg. To keep the expenditure fixed, their consumption for this month should be 16x/20 = 4x/5. Reduction in consumption = x/5 = 20% of x
43. Answer: Option 'C' New volume = (1/2) × (b/2) × 2h = (lbh/2) So, there is 50% decrease.
44. Answer: Option 'D' Runs scored in boundaries and sixes = (13 × 4) + (3 × 6) = 52 + 18 = 70 Runs Scored between the wickets = 100 -70 = 30 30% of the runs are scored by running between the wickets.
45. Answer: Option 'C' After selling 35% of the apples, he has 65% left. (65/100) × x = 260x = 400
47. Answer: Option 'C' The present population = (102/100) × (103/100) × (105/100) × 100000 = 1,10,313
48. Answer: Option 'D' Let the number of valid votes be x Winning candidate - 58% of x Other candidate - 42% of x Difference - 16% of x 16% of x = 1600 x = 10000 Total votes = 10000 + 100 = 10100
49. Answer: Option 'B' He scored 7% less than the maximum marks. 7% of x = 84 x = 1200
50. Answer: Option 'C' Let their marks be (x + 9) and x. Then, x + 9 = (56/100)(x+9+x) 25(x+9) = 14(2x + 9) 3x = 99 x = 33 So, their marks are 42 and 33.
1-c
ReplyDelete2-a
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8-b or c
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14-d
15-a
16-b
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18-d
19-b
20-d
21-a
22-c
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50-c
1. Answer: Option 'C'
ReplyDelete33 1/3 % = 1/3
1/3 × 240 = 80
2. Answer: Option 'A'
11 1/9 % = 1/9
1/9 × 900 = 100
3. Answer: Option 'C'
2/5 × 100 % = 200/5 % = 40 %
4. Answer: Option 'C'
3/4 × 100 = 300/4 % = 75 %
5. Answer: Option 'A'
70/280 = 1/4
1/4 × 100 = 25 %
6. Answer: Option 'C'
120/90 = 4/3
4/3 × 100 = 400/3 = 133 1/3 %
7. Answer: Option 'B'
1 kg = 1000 gm
5/1000 × 100 = 500/1000
=1/2 = 0.5 %
8. Answer: Option 'A'
12 Rupees = 1200paisa's
36/1200 × 100 = 3/12
12/3 = 3 %
9. Answer: Option 'C'
Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-"
A number means = 100 %
That same number increased by 20 % = 120 %
120 % -------> 480 (120 × 4 = 480)
100 % -------> 400 (100 × 4 = 400)
10. Answer: Option 'A'
Let the marks secured by them be x and (x + 9)
Then sum of their marks = x + (x + 9) = 2x + 9
Given that (x + 9) was 56% of the sum of their marks
=>(x+9) = 56/100(2x+9)
=>(x+9) = 14/25(2x+9)
=> 25x + 225 = 28x + 126
=> 3x = 99
=> x = 33
Then (x + 9) = 33 + 9 = 42
Hence their marks are 33 and 42
11. Answer: Option 'C'
ReplyDelete20% of a = b
=> b = 20/100a
b% of 20 = (b/100)20 = [(20/100a)/100]20
= (20 × 20 × a)/(100 × 100)
= 4a/100 = 4% of a
12. Answer: Option 'C'
Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250
13. Answer: Option 'A'
Total cost of the items he purchased = Rs.25
Given that out of this Rs.25, 30 Paise is given as tax
=> Total tax incurred = 30 Paise = Rs.30/100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (25−30/100−x)6/100 = 30/100
⇒ 6(25 −0.3 −x) = 30
⇒ (25 − 0.3 − x) = 5
⇒ x = 25 − 0.3 − 5 = 19.7
14. Answer: Option 'C'
Quantity X Rate = Price
1 x 1 = 1
0.7 x 1.25 = 0.875
Decrease in price = (0.125/1) × 100 = 12.5%
15. Answer: Option 'A'
State A and State B had an equal number of candidates appeared.
In state A, 6% candidates got selected from the total appeared candidates
In state B, 7% candidates got selected from the total appeared candidates
But in State B, 80 more candidates got selected than State A
From these, it is clear that 1% of the total appeared candidates in State B = 80
=> total appeared candidates in State B = 80 x 100 = 8000
=> total appeared candidates in State A = total appeared candidates in State B = 8000
16. Answer: Option 'B'
Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-"
A number means = 100 %
That same number Decreased by 20 % = 80 %
80 % ------> 480 (80 × 6 = 480)
100 % ------> 600 (100 × 6 = 600)
17. Answer: Option 'B'
20% = 20 × 4 = 80
30% = 30 × 4= 120
18. Answer: Option 'D'
40% = 40 × 3 = 120
90% = 90 × 3 = 270
19. Answer: Option 'B'
Farmula = AFTER INCREASED 10% × AFTER REDUCED 10%/TOTAL 100%
= 110 × 90/100 = 99 %
= Decreases by 1%
20. Answer: Option 'C'
Quantity X Rate = Price
1 x 1 = 1
0.7 x 1.25 = 0.875
Decrease in price = (0.125/1) × 100 = 12.5%
21. Answer: Option 'A'
ReplyDeleteA = 125
B = 100
A-B/A × 100 = 25/125 × 100 = 20 % smaller smaller than A
22. Answer: Option 'C'
X = 120%
Y = 125%
Z = 100%
X-Y/Y × 100 = 5/125 × 100 = 4 % smaller than Y
23. Answer: Option 'C'
X = 80 %
Y = 70 %
Z = 100 %
X-Y/X × 100 = 10/80 × 100 = 12 1/2 % greater than X
24. Answer: Option 'B'
X = 120
Y = 100
Z = 80
X-Z/Z × 100 = 40/80 × 100 = 50 % greater than Z
25. Answer: Option 'A'
Total = 100 %,
First person got 60%
second person got remaining 40 % of votes.
than 40 % = 280
40% = 40×7 = 280
100% =100×7 =700votes
26. Answer: Option 'B'
Note : majority (20 %) = difference in votes polled to win (60 %) & defeated candidates (40 %)
20 % = 60 % - 40 %
20% -----> 280 (20×14 = 280 )
100% -----> 1400 (100×14 = 1400)
27. Answer: Option 'C'
100 % - 10 % = 90 %
54%-36%=18%
18% ------> 1800 ( 18 × 100 = 1800)
100% -------> 10000 votes (100 × 100 = 10000)
28. Answer: Option 'B'
(100%-20%=80%
48%-32%=16%
16% = 16×30 = 480
100% =100×30 =3000 votes)
29. Answer: Option 'C'
Formula :
( After =100 denominator
Ago = 100 numerator)
10000 × 120/100 × 120/100 = 14400
30. Answer: Option 'B'
Formula :
( After =100 denominator
Ago = 100 numerator)
8000 × 80/100 × 80/100 = 5120
31. Answer: Option 'C'
ReplyDeleteFormula :
( After =100 denominator
Ago = 100 numerator)
8100 × 100/90 × 100/90 = 10000
32. Answer: Option 'C'
Formula :
( After =100 denominator
Ago = 100 numerator)
13200 × 100/110 × 100/120 = 10000
33. Answer: Option 'A'
30 % -------> 120 ( 30 × 4 = 120)
100% -------> 400 (100 × 4 = 400)
34. Answer: Option 'C'
40 % ------> 120 ( 40 × 3 = 120 )
100 % ------> 300 ( 100 × 3 = 300 )
35. Answer: Option 'A'
passed in Telugu = 60 %
passed in English = 50 %
only passed in telugu = 50%
only passed in english = 40%
the percentage of studebts passed in both the subjects = 10 %
36. Answer: Option 'B'
only telugu passed = 50 %
only english passed = 40 %
both subjects passed student are 10 %,
Then,
10 % ------> 120
100 % ------> 1200students
37. Answer: Option 'B'
only t = 40,only e = 30 and both subjects passed 20%
10% failed in both subjects
38. Answer: Option 'C'
(20 li = 4 li water 16 li milk
-------- 5 li water
Total = 9 li water 16 li milk (new)
16/25×100=64%
39. Answer: Option 'D'
(30 li = 9 li water 21 li milk
------= 10 li water
Total = 19li water 21 li milk (new)
19/40 × 100 = 47 1/2%
40. Answer: Option 'C'
she spend = 50% remaining 50% = 5760/-
100%=11520/-
41. Answer: Option 'B'
ReplyDeleteFORMULA:
First value = last value×100/100-p1×100/100-p2×---------------- (p=percentage)
First value = 5760×100/100 - 20×100/100 - 10×100/100 - 20
= 5760 × 100/80× 100/90× 100/80 = 10000/-
42. Answer: Option 'C'
Let a family's monthly consumption of daal be x kg.
To keep the expenditure fixed,
their consumption for this month should be 16x/20 = 4x/5.
Reduction in consumption = x/5 = 20% of x
43. Answer: Option 'C'
New volume = (1/2) × (b/2) × 2h = (lbh/2)
So, there is 50% decrease.
44. Answer: Option 'D'
Runs scored in boundaries and sixes = (13 × 4) + (3 × 6) = 52 + 18 = 70 Runs
Scored between the wickets = 100 -70 = 30
30% of the runs are scored by running between the wickets.
45. Answer: Option 'C'
After selling 35% of the apples, he has 65% left.
(65/100) × x = 260x = 400
46. Answer: Option 'B'
There are 13 numbers.
(7, 17, 27, 37, 47, 57, 67, 70, 71, 72, 73, 74, 75) * 100 = 17.33%
47. Answer: Option 'C'
The present population = (102/100) × (103/100) × (105/100) × 100000 = 1,10,313
48. Answer: Option 'D'
Let the number of valid votes be x
Winning candidate - 58% of x
Other candidate - 42% of x
Difference - 16% of x
16% of x = 1600
x = 10000
Total votes = 10000 + 100 = 10100
49. Answer: Option 'B'
He scored 7% less than the maximum marks.
7% of x = 84 x = 1200
50. Answer: Option 'C'
Let their marks be (x + 9) and x.
Then, x + 9 = (56/100)(x+9+x)
25(x+9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.