Train covers a distance of 3584 km in 2 days 8 hours. if it cover 1440 km
on 1st day and 1608 km on the 2nd day. by how much does the average speed of
the train for the remaining part of the journey differ from that for the entire
journey?
A. 3
kmph more
B. 3
kmph less
C. 4
kmph less
D. 5
kmph less
Average speed = Total Distance traveled/Total time taken
ReplyDeleteTotal time = 2 days + 8 hours = 56 hours
Average speed = 3584/56 = 64 km/hr
remaining part of journey = 3584 - (1440 + 1608) = 536 km
remaining time = 8 hours
Average speed of remaining part of journey = 536/8 = 67 km/hr
= 67 - 64
= 3 km/hr