1.
A girl decided to
read a book of 1000 pages in 20 days, reading 5 hrs/day. How many days will she
take to read a book of 1500 days with a rate of 2 hrs/day?
A.50 B.75 C.65 D.70
2.
27.92% of
425.02-24.03% of 299.97= (?)
A.27 B.77 C.47 D.25
3.
If 5 years before
the ratio of ages of daughter and father is 3 : 15. After 5 years from now the
ratio will become 8: 20. Then Find out the age of the father?
A.25 B.30 C.35 D.40
4.
Pooja scored 60 %
of marks in Hindi, 70% marks in Science and ” M” marks in Maths. If Maximum marks
of each subject is 150 and he scored 70% marks. Then find the marks he scored in
Maths?
A.110 B.120 C.130 D.140
5.
From a group of 6
soldiers and 4 police a committee of 5 people is formed for emergency rescue
operation. The
committee is to be formed having at least 3 soldiers. Find the number of
possible ways?
A.160 B.170 C.186 D.190
Option B
ReplyDelete1 day= 5hrs=> 20 days = 20 x 5=100hrs
she can read 1000 pages in 100 hrs.
so for 1 hr = 1000/100 = 10 pages she can complete.
Then 2 hrs , 20 pages she can complete.
Per day 20 pages , then for 1500 pages = 1500/20 = 75 days to complete.
Option C
ReplyDeleteSubstituting (?) with “x”
x=28%×425-24%×300
x =119 – 72
x=47
3)
ReplyDeleteOption C
Let the age of daughter before 5 years= 3x
Let the age of father before 5 years = 15x
Then , (3x + 10/15x+10) = 8/20
=>x=2
So age of father before 5 years= 15x= 15*2 = 30 years
present age = 30+ 5= 35 years
4)
ReplyDeleteOption B
Marks in Hindi = 60/100 * 150 = 90
Marks in Science = 70/100 * 150 = 105
Total marks in 3 subjects = 70/100 * 450 =315
so 90 + 105 +M = 315
=> M= 120
5)
ReplyDeleteOption C
(6C3 * 4C2) + ( 6C4 * 4C1 ) + 6C5 = 120 +60 + 6 = 186