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1. A 48 litres solution contains liquids water and milk in the ratio 3 : 5. How much amount of milk is to be added so that amount of milk is 70% of the new solution?
A) 26 l
B) 20 l
C) 12 l
D) 18 l
E) 15 l
2. In a class, average age of 30 students is 18 years. If the age of 2 more students is taken into consideration, then the average of all students gets increase by 1. Find the average of the ages of those 2 students.
A) 50
B) 68
C) 54
D) 34
E) 38
B) 15
C) 22
D) 28
E) 34
1. A 48 litres solution contains liquids water and milk in the ratio 3 : 5. How much amount of milk is to be added so that amount of milk is 70% of the new solution?
A) 26 l
B) 20 l
C) 12 l
D) 18 l
E) 15 l
2. In a class, average age of 30 students is 18 years. If the age of 2 more students is taken into consideration, then the average of all students gets increase by 1. Find the average of the ages of those 2 students.
A) 50
B) 68
C) 54
D) 34
E) 38
3.The ratio of A’s age 3 years ago and B’s age 5 years hence is 3 : 4. The average of the ages of A and C is 20 years. Also C’s age after 10 years will be 2 more than twice the age present age of B. Find the age of C.
A) 18B) 15
C) 22
D) 28
E) 34
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1. C) 12 l
ReplyDeleteSolution:
Water present in solution = 3/8 * 48 = 18 l
Milk present in solution = 5/8 * 48 = 30 l
Let x litres of milk to be added
Milk is to be 70% of new solution, so water is to be 30% of new solution. So
30/100 of new solution = Water present in new solution
30/100 * (48+x) = 18
So, x = 12 litres
OR
70/100 of new solution = Milk present in new solution
70/100 * (48+x) = 30+x
So, x = 12 litres
2. D) 34
ReplyDeleteSolution:
30 students – 18
32 students – 19
So total age of those 2 students = 30×1 + 19×2 = 68
So average = 68/2 = 34
3. C) 22
ReplyDeleteSolution:
(A – 3)/(B + 5) = 3/4
(A + C)/2 = 20 and
C + 10 = 2B + 2