1. A man
takes 6 hrs 30 min in walking to a certain place and riding back. He would have
gained 2 hrs 10 min by riding both ways. How long would he take to walk both
ways?
(a) 8 hr 30 min
(b) 8 hr 40 min
(c) 8 hr 50 min
(d) 9 hr
(e) None of these
2. A Train
which travels at the uniform rate of 10 m a second leaves Madras for Arconum at
7 a.m. At what distance from Madras will it meet a train which leaves Arconum
for Madras at 7.20 a.m., and travels one-third faster than the former does, the
distance from Madras to Arconum being 68 km?
(a) 40
(b) 38
(c) 36
(d) 34
(e) None of these
3. A, B and C
can walk at the rates of 3, 4 and 5 km an hour respectively. They start from
Poona at 1, 2, 3 o’clock respectively. When B catches A, B sends him back with
a message to C. When will C get the message?
(a) 5.15
(b) 5.20
(c) 5.30
(d) 6.00
(e) None of these
4. Two men start
together to walk a certain distance, one at 3 (3/4) km an hour and
the other at 3 km an hour. The former arrives half an hour before the latter.
Find the distance.
(a) 7 km
(b) 7.5 km
(c) 8 km
(d) 8.5 km
(e) None of these
1. Ans.(b)
ReplyDeleteSol. Walking + Riding = 6 hrs 30 min ……(1)
2 Riding = 6 hrs 30 min – 2 hrs 10 min
= 4 hrs 20 min ……(2)
Solving the above two relations (equations);
2 × (1) – (2) gives
2 walking = 13 hrs – 4 hrs 20 min = 8 hrs 40 minutes
2. Ans.(c)
ReplyDeleteSol. S1 = 10 * 18/5 = 36 km/hr
S2 = 36 + 36/3 = 48 km/hr
Difference in time = T1 – T2 = 7 am – 7.20 am = 1/3 hr
Distance of meeting point from madras
3. Ans.(a)
ReplyDeleteSol. Speed Starting time
A takes a lead of 3 km from B.
Relative speed of A and B = 4 – 3 = 1 km/hr
B catches A after 3/1 = 3 hrs, i.e., at 2 + 3 = 5 o’clock.
A returns at 5 o’clock and from a distance of 3 × 4 = 12 km from Poona.
In the meantime C covers a distance of 5 × 2 = 10 km from Poona.
Thus, A and C are 12 – 10 = 2 km apart at 5 O’clock.
Relative speed of A and C = 3 + 5 = 8 km/hr.
Thus, they meet after 2/8 = 1/4 hr = 15 min.
Thus, C will get the message at 5.15 o’clock.