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Thursday, 30 August 2018
Time and work
A
and B can finish a work together in 12 days, and B and C together in 16 days.
If A alone works for 5 days and then B alone continues for 7 days, then
remaining work is done by C in 13 days. In how many days can C alone finish the
complete work?
Total work = 48 unit efficiency of a+b =4 ————-(1) efficiency of b+c =3 ————-(2) According to question 5a +7b +13c = 48 now using 1 and 2 equation 5a+ 7(4-a) +13(a-1) =48 11a =33 a=3 , b =1 , c = 2 Time taken by C = 48/2 =24 days
Total work = 48 unit
ReplyDeleteefficiency of a+b =4 ————-(1)
efficiency of b+c =3 ————-(2)
According to question
5a +7b +13c = 48
now using 1 and 2 equation
5a+ 7(4-a) +13(a-1) =48
11a =33
a=3 , b =1 , c = 2
Time taken by C = 48/2 =24 days