Tuesday, 21 March 2017

Question of the day 21-3-2017

Directions: Each question below contains a statement followed by Quantity I and Quantity II. Find both to find the relationship among them. Mark your answer accordingly.
1.  If x and y are natural numbers and 5 > x > y > 0.
Quantity I: 3x2y
Quantity II: 4xy2
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≤ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
2.  A and B started a business with Rs 10,000 and Rs 15,000 respectively. After 6 months C joined them with Rs 20,000.
Quantity I: B′s share in total profit of Rs 4,00,000 at the end of 2 years.
Quantity II: Annual Salary of Rohit after tax deduction if he earns Rs 20,000 per month and pays a tax of 20% each month.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≤ Quantity I
E) Quantity I = Quantity II or Relation cannot be established

3.  A can do a work in 16 days. B is 60% more efficient than A.
Quantity I: Time taken by A and B together to do the work.
Quantity II: Time taken by A and B to do the work together when A works at double his original efficiency and B works at half his original efficiency.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established

3 comments:

  1. 1. Option B
    Explanation:
    Divide both equations. So
    I/II = 3x/4y
    Or I = 3x/4y * II
    Now y has to be > 0 and x has to be > y
    If x = 2, y = 1, I > II
    If x = 3, y = 1, I > II
    Similarly we will get I > II in all cases
    Now x has to be < 5,
    So check If x = 4, y = 3, then I = II
    So final we get I ≥ II

    2. Option C
    Explanation:
    I: A:B:C = 10000*24 : 15000*24 : 20000*18=2:3:3
    B=3/8 *4,00,000= Rs 1,50,000
    II: Salary after deducation = 20,000*12*80/100 = Rs 1,92,000
    Hence I < II


    3. Option A
    Explanation:
    I: A=16 days ; B = 16 * 100/160=10 days
    A+B together = 16*10/(26)=80/13 days
    II: A = 16 days ; B = 10 days
    A(double efficiency) = 8 days ; B(half efficiency) = 20 days
    A+B together = 80/14
    hence I > II

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