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Saturday 4 March 2017
Question of the day 5-3-2017
How many alphabets need to be there in a
language if one were to make 1 million distinct 3 digit initials
using the alphabets of the language?
Answer: Option b Explanation: 1 million distinct 3 digit initials are needed. Let the number of required alphabets in the language be n. Therefore, using n alphabets we can form n×n×n=n3 distinct 3 digit initials. Note: Distinct initials are different from initials where the digits are different. For instance, AAA and BBB are acceptable combinations in the case of distinct initials while they are not permitted when the digits of the initials need to be different. This n^3 different initials =1 million i.e. n^3=〖10〗^6 (1 million =106=) ⇒ n^3=〖(〖10〗^2)〗^3 ⇒ n=100 Hence, the language needs to have a minimum of 100 alphabets to achieve the objective.
Answer: Option b
ReplyDeleteExplanation:
1 million distinct 3 digit initials are needed.
Let the number of required alphabets in the language be n.
Therefore, using n alphabets we can form n×n×n=n3 distinct 3 digit initials.
Note: Distinct initials are different from initials where the digits are different.
For instance, AAA and BBB are acceptable combinations in the case of distinct initials while they are not permitted when the digits of the initials need to be different.
This n^3 different initials =1 million
i.e. n^3=〖10〗^6 (1 million =106=)
⇒ n^3=〖(〖10〗^2)〗^3
⇒ n=100
Hence, the language needs to have a minimum of 100 alphabets to achieve the objective.